Review and Problem Solving in Electrochemistry
From the Engineering Chemistry curriculum
TL;DR
Electrochemistry deals with the relationship between chemical reactions and electricity, focusing on redox reactions where electrons are transferred. You'll work with electrochemical cells (voltaic/galvanic for generating electricity, electrolytic for driving non-spontaneous reactions) and use concepts like electrode potentials, Gibbs free energy, and the Nernst equation to understand and quantify these processes. Mastering problem-solving involves identifying redox species, applying relevant formulas, and interpreting cell notation.
1. The Mental Model
Think of electrochemistry as a way to either create electricity from a chemical reaction (like a battery) or use electricity to force a chemical reaction to happen (like electroplating). It's all about how electrons move during these chemical changes.
2. The Core Material
Electrochemistry is built on understanding redox reactions (reduction-oxidation).
* Oxidation is the loss of electrons (increase in oxidation state).
* Reduction is the gain of electrons (decrease in oxidation state).
These reactions happen at electrodes:
* Anode: Where oxidation occurs. It's the negative electrode in a voltaic cell and the positive electrode in an electrolytic cell.
* Cathode: Where reduction occurs. It's the positive electrode in a voltaic cell and the negative electrode in an electrolytic cell.
Electrochemical Cells

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There are two main types of electrochemical cells:
-
Voltaic (Galvanic) Cells:
- Generate electrical energy from a spontaneous chemical reaction.
- Example: A standard battery.
- The overall cell potential ($E_{cell}$) is positive.
-
Electrolytic Cells:
- Use electrical energy to drive a non-spontaneous chemical reaction.
- Example: Electroplating, refining metals.
- The overall cell potential ($E_{cell}$) is negative, meaning an external power source is needed.
Key Equations and Concepts

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- Standard Electrode Potential ($E^\circ$): The potential of a half-cell under standard conditions (1 M concentration for ions, 1 atm pressure for gases, 298 K). Reduction potentials are usually tabulated.
- Standard Cell Potential ($E^\circ_{cell}$):
$E^\circ_{cell} = E^\circ_{cathode} - E^\circ_{anode}$ (where both are standard reduction potentials).
A positive $E^\circ_{cell}$ indicates a spontaneous reaction (voltaic cell). - Gibbs Free Energy ($\Delta G$): Relates cell potential to spontaneity.
$\Delta G = -nFE_{cell}$
Where:- $n$ is the number of moles of electrons transferred in the balanced reaction.
- $F$ is Faraday's constant (96,485 C/mol e$^-$).
- If $\Delta G < 0$, the reaction is spontaneous. This corresponds to $E_{cell} > 0$.
- Nernst Equation: Used to calculate cell potential under non-standard conditions.
$E_{cell} = E^\circ_{cell} - \frac{RT}{nF} \ln Q$
At 298 K: $E_{cell} = E^\circ_{cell} - \frac{0.0592}{n} \log Q$
Where:- $R$ is the ideal gas constant (8.314 J/(mol·K)).
- $T$ is temperature in Kelvin.
- $Q$ is the reaction quotient (same form as equilibrium constant $K_c$ but with non-equilibrium concentrations).
Cell Notation

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A shorthand way to represent an electrochemical cell:
Anode | Anode Ion || Cathode Ion | Cathode
Example: $\text{Zn(s)} | \text{Zn}^{2+}\text{(aq, 1 M)} || \text{Cu}^{2+}\text{(aq, 1 M)} | \text{Cu(s)}$
* Single vertical line (|) represents a phase boundary.
* Double vertical line (||) represents a salt bridge.
Here's how to think about building a voltaic cell:
graph TD
A["Identify two half-reactions (oxidation/reduction)"] --> B{"Is it spontaneous (voltaic)?"}
B -- Yes --> C["Assign more negative reduction potential to anode (oxidation)"]
B -- No --> D["Need external power (electrolytic)"]
C --> E["Calculate E_cell = E_cathode - E_anode"]
E --> F["Write cell notation: Anode | Anode Ion || Cathode Ion | Cathode"]
D --> E
3. Worked Example
Consider a voltaic cell made from a silver electrode in 1.0 M AgNO$_3$ and a cadmium electrode in 1.0 M Cd(NO$_3$)$_2$.
Given standard reduction potentials:
$\text{Ag}^+\text{(aq)} + \text{e}^- \rightarrow \text{Ag(s)}$; $E^\circ = +0.80 \text{ V}$
$\text{Cd}^{2+}\text{(aq)} + 2\text{e}^- \rightarrow \text{Cd(s)}$; $E^\circ = -0.40 \text{ V}$
-
Identify Anode and Cathode: The more positive standard reduction potential is for reduction (cathode). So, Ag$^+$ will be reduced. The more negative potential is for oxidation (anode). So, Cd will be oxidized.
- Cathode (Reduction): $\text{Ag}^+\text{(aq)} + \text{e}^- \rightarrow \text{Ag(s)}$
- Anode (Oxidation): $\text{Cd(s)} \rightarrow \text{Cd}^{2+}\text{(aq)} + 2\text{e}^-$
-
Balance Electrons and Write Overall Reaction: Multiply the silver half-reaction by 2 to balance electrons.
- $2\text{Ag}^+\text{(aq)} + 2\text{e}^- \rightarrow 2\text{Ag(s)}$
- $\text{Cd(s)} \rightarrow \text{Cd}^{2+}\text{(aq)} + 2\text{e}^-$
- Overall: $2\text{Ag}^+\text{(aq)} + \text{Cd(s)} \rightarrow 2\text{Ag(s)} + \text{Cd}^{2+}\text{(aq)}$
-
Calculate $E^\circ_{cell}$:
$E^\circ_{cell} = E^\circ_{cathode} - E^\circ_{anode} = (+0.80 \text{ V}) - (-0.40 \text{ V}) = +1.20 \text{ V}$
Since $E^\circ_{cell}$ is positive, the reaction is spontaneous. -
Calculate $\Delta G^\circ$:
$n = 2$ (moles of electrons transferred)
$\Delta G^\circ = -nFE^\circ_{cell} = -(2 \text{ mol e}^-)(96,485 \text{ C/mol e}^-)(1.20 \text{ V})$
$\Delta G^\circ = -231,564 \text{ J} = -231.6 \text{ kJ}$ -
Write Cell Notation:
$\text{Cd(s)} | \text{Cd}^{2+}\text{(aq, 1 M)} || \text{Ag}^+\text{(aq, 1 M)} | \text{Ag(s)}$
4. Key Takeaways
- Redox reactions are fundamental: Always identify what's being oxidized (losing electrons) and reduced (gaining electrons).
- Electrode potentials predict spontaneity: A more positive $E^\circ_{cell}$ means a more spontaneous reaction, which is characteristic of voltaic cells.
- Nernst equation handles non-standard conditions: Use it when concentrations aren't 1 M or pressure isn't 1 atm.
- Faraday's constant links charge and moles: It's crucial for calculations involving current, time, and mass deposited/consumed.
- Cell notation is a standardized summary: It tells you the setup of the cell, including anode, cathode, and phases.
Common Mistakes to Avoid:
* Flipping signs of potentials: Always use standard reduction potentials for $E^\circ_{cathode}$ and $E^\circ_{anode}$.
* Not balancing electrons: Ensure the number of electrons lost in oxidation equals the number gained in reduction for the overall reaction.
* Confusing anode/cathode in voltaic vs. electrolytic cells: Anode is always where oxidation occurs, cathode where reduction occurs, but their polarity changes depending on the cell type.
* Incorrectly applying the Nernst equation: Remember $Q$ (reaction quotient) has products in the numerator and reactants in the denominator, raised to their stoichiometric coefficients.
5. Now Try It
You have a voltaic cell composed of a standard iron electrode (Fe$^{2+}$/Fe) and a standard nickel electrode (Ni$^{2+}$/Ni).
Given: $E^\circ(\text{Fe}^{2+}/\text{Fe}) = -0.44 \text{ V}$ and $E^\circ(\text{Ni}^{2+}/\text{Ni}) = -0.25 \text{ V}$.
- Determine which electrode is the anode and which is the cathode.
- Write the balanced overall cell reaction.
- Calculate the standard cell potential ($E^\circ_{cell}$).
- Write the cell notation for this voltaic cell.
Success looks like: correctly identifying the anode and cathode based on their reduction potentials, balancing the electron transfer for the overall reaction, calculating a positive $E^\circ_{cell}$, and writing the cell notation correctly.
Frequently asked about Review and Problem Solving in Electrochemistry
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