Electrochemistry: Galvanic Cells
From the Oxidation and reduction reaction curriculum
TL;DR
Galvanic cells (or voltaic cells) convert chemical energy from spontaneous redox reactions into electrical energy by separating the oxidation and reduction half-reactions. Electrons flow from the anode (oxidation) to the cathode (reduction) through an external circuit, creating an electric current. A salt bridge maintains electrical neutrality by allowing ion migration between the half-cells.
1. The Mental Model
Imagine a chemical "tug-of-war" where one side (the anode) really wants to give up electrons and the other side (the cathode) really wants to take them. A galvanic cell is just a clever way to make these electrons take a detour through a wire to do useful work before they get to their destination.
2. The Core Material
Galvanic cells are devices that harness the energy released from a spontaneous redox reaction to produce electrical current. This spontaneity means the reaction occurs naturally without external energy input.
The key components of a galvanic cell are:
* Anode: The electrode where oxidation occurs. It's negatively charged because it's the source of electrons.
* Cathode: The electrode where reduction occurs. It's positively charged because it accepts electrons.
* Electrolyte: An ion-conducting solution in each half-cell where the electrodes are immersed.
* External Circuit (Wire): Connects the anode and cathode, allowing electrons to flow from the anode to the cathode.
* Salt Bridge: A U-shaped tube containing an inert electrolyte (like KNO₃ or NaCl). It connects the two half-cells, allowing ions to migrate to maintain electrical neutrality and complete the circuit. Without it, charge would build up, and the reaction would stop.
How a Galvanic Cell Works

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- Oxidation at the Anode: The more easily oxidized metal (or species) loses electrons. These electrons then travel through the external wire. The anode itself often corrodes or dissolves.
- Electron Flow: Electrons move from the anode (negative) through the wire to the cathode (positive). This flow is the electric current.
- Reduction at the Cathode: At the cathode, the less easily oxidized metal's ions (or other species) gain electrons and are reduced, often plating onto the electrode.
- Ion Migration in Salt Bridge: To prevent charge buildup, anions from the salt bridge migrate towards the anode (to balance the positive charge from metal ions entering the solution), and cations from the salt bridge migrate towards the cathode (to balance the negative charge from ions being consumed).
Here's a visual representation of the electron and ion flow:
graph TD
A["Anode (Oxidation)"] -->|Electrons (e-)| W["External Wire"]
W --> C["Cathode (Reduction)"]
S["Salt Bridge"] -->|Anions (e.g., NO3-)| A
S -->|Cations (e.g., K+)| C
A -->|Metal Ions (e.g., Zn2+)| A_Sol["Anode Solution"]
C_Sol["Cathode Solution"] -->|Metal Ions (e.g., Cu2+)| C
Cell Notation

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Galvanic cells can be represented using a shorthand notation:
Anode | Anode Solution || Cathode Solution | Cathode
- A single vertical line ( | ) represents a phase boundary (e.g., solid electrode in liquid solution).
- A double vertical line ( || ) represents the salt bridge.
- The anode (oxidation) is always on the left, and the cathode (reduction) is always on the right.
- For example, a Daniel cell (zinc-copper cell) would be: Zn(s) | Zn²⁺(aq) || Cu²⁺(aq) | Cu(s)
3. Worked Example
Let's consider a standard Daniel cell composed of a zinc electrode in ZnSO₄ solution and a copper electrode in CuSO₄ solution, connected by a salt bridge.
-
Identify half-reactions:
- Zinc is more easily oxidized than copper. So, zinc will be the anode.
- Oxidation (Anode): Zn(s) → Zn²⁺(aq) + 2e⁻
- Copper ions will be reduced at the cathode.
- Reduction (Cathode): Cu²⁺(aq) + 2e⁻ → Cu(s)
- Zinc is more easily oxidized than copper. So, zinc will be the anode.
-
Overall reaction: Add the half-reactions, ensuring electrons cancel out.
- Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)
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Electron flow: Electrons are released by the oxidation of Zn at the anode and flow through the wire to the cathode, where Cu²⁺ ions accept them.
-
Ion movement in salt bridge: If the salt bridge contains KNO₃:
- NO₃⁻ ions (anions) would move towards the anode compartment to balance the buildup of positive Zn²⁺ ions.
- K⁺ ions (cations) would move towards the cathode compartment to balance the consumption of positive Cu²⁺ ions.
4. Key Takeaways
- Galvanic cells convert chemical energy from spontaneous redox reactions into electrical energy.
- Oxidation always occurs at the anode (negative electrode), and reduction always occurs at the cathode (positive electrode).
- Electrons flow from the anode to the cathode through the external wire.
- The salt bridge is crucial for maintaining charge neutrality by allowing ion migration, completing the circuit.
- The cell notation always lists the anode on the left and the cathode on the right.
Common Mistakes to Avoid

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- Confusing anode and cathode, or oxidation and reduction location. Remember "An Ox" (Anode = Oxidation) and "Red Cat" (Reduction = Cathode).
- Forgetting the role of the salt bridge; the reaction will stop without it.
- Incorrectly assigning the direction of electron flow (always anode to cathode externally).
- Not balancing the charges with spectator ions or incorrectly indicating ion movement in the salt bridge.
5. Now Try It
Design a galvanic cell using a silver electrode in a AgNO₃ solution and a lead electrode in a Pb(NO₃)₂ solution.
- Write the oxidation half-reaction.
- Write the reduction half-reaction.
- Write the overall balanced redox reaction.
- Indicate which electrode is the anode and which is the cathode.
- Draw a simple diagram showing the electrodes, solutions, salt bridge, and the direction of electron flow.
Success looks like: You've correctly identified lead as the anode and silver as the cathode, written balanced half-reactions and the overall reaction, and shown electrons flowing from the lead electrode to the silver electrode.
Frequently asked about Electrochemistry: Galvanic Cells
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