Chemical Properties of Alcohols
From the Alcohol phenol and ether curriculum
TL;DR
Alcohols are versatile organic compounds that undergo various reactions, primarily due to the polarity of their O-H bond and the presence of the lone pair on the oxygen atom. These reactions can be broadly categorized into those involving the breaking of the O-H bond (acidity), the C-O bond (nucleophilic substitution), or oxidation. Understanding these reactions helps predict how alcohols will behave in different chemical environments.
1. The Mental Model
Think of the alcohol molecule (R-O-H) as having two "reactive spots": the slightly acidic hydrogen on the -OH group and the oxygen atom with its lone pairs, which can act as a nucleophile or be oxidized. Depending on the reaction conditions, one of these spots will be more reactive, leading to different chemical outcomes.
2. The Core Material
Alcohols participate in a wide array of reactions. We'll break them down by the type of bond cleavage or functional group transformation.
Reactions Involving Cleavage of O-H Bond (Acidity)
The oxygen atom is more electronegative than hydrogen, making the O-H bond polar. This polarity allows the hydrogen to be removed as a proton (H⁺) under certain conditions, indicating acidic behavior.
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Reaction with Active Metals: Alcohols react with active metals like sodium (Na) or potassium (K) to form alkoxides and hydrogen gas. This demonstrates their weakly acidic nature.
2R-O-H + 2Na → 2R-O⁻Na⁺ + H₂
(Alcohol) + (Sodium) → (Sodium Alkoxide) + (Hydrogen Gas) -
Acidity Order:
Primary alcohol > Secondary alcohol > Tertiary alcohol
This order is due to the electron-donating inductive effect of alkyl groups, which destabilizes the alkoxide ion, making it harder for the alcohol to release a proton. Water is generally more acidic than alcohols.
Reactions Involving Cleavage of C-O Bond (Nucleophilic Substitution)

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For the C-O bond to break, the -OH group needs to be converted into a better leaving group, usually by protonating it to form -OH₂⁺ (water, a very good leaving group).
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Reaction with Hydrogen Halides (HX): Alcohols react with strong acids like HX (HCl, HBr, HI) to form alkyl halides and water. This is a nucleophilic substitution reaction (S_N1 or S_N2) where the halide ion acts as the nucleophile.
R-O-H + HX → R-X + H₂O- Reactivity Order of Alcohols:
Tertiary > Secondary > Primary(follows S_N1 mechanism preference for tertiary due to carbocation stability). - Reactivity Order of Hydrogen Halides:
HI > HBr > HCl.
- Reactivity Order of Alcohols:
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Reaction with Phosphorus Halides (PX₃, PX₅) or Thionyl Chloride (SOCl₂): These reagents are often preferred for converting alcohols to alkyl halides because they avoid carbocation rearrangements and often produce gaseous byproducts that are easy to separate.
R-O-H + PCl₅ → R-Cl + POCl₃ + HCl
3R-O-H + PCl₃ → 3R-Cl + H₃PO₃
R-O-H + SOCl₂ → R-Cl + SO₂ + HCl(Thionyl chloride is particularly good as SO₂ and HCl are gases) -
Dehydration to Alkenes: In the presence of strong protic acids (like concentrated H₂SO₄ or H₃PO₄) and heat, alcohols undergo dehydration to form alkenes. This involves the protonation of the -OH group, formation of a carbocation, and subsequent elimination of a proton.
R-CH₂-CH₂-OH --(H₂SO₄, heat)--> R-CH=CH₂ + H₂O- Reactivity Order:
Tertiary > Secondary > Primary(due to carbocation stability, similar to S_N1). - Zaitsev's Rule: If multiple alkenes can be formed, the major product is usually the most substituted (most stable) alkene.
- Reactivity Order:
Oxidation Reactions

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Oxidation of alcohols involves the removal of hydrogen atoms or the addition of oxygen atoms. The product depends on the type of alcohol (primary, secondary, tertiary) and the strength of the oxidizing agent.
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Primary Alcohols (R-CH₂-OH):
- Mild Oxidation (e.g., PCC - Pyridinium Chlorochromate): Forms aldehydes. PCC is selective and stops at the aldehyde stage.
R-CH₂-OH --(PCC)--> R-CHO(Aldehyde) - Strong Oxidation (e.g., K₂Cr₂O₇/H⁺, KMnO₄/H⁺): Forms carboxylic acids. The aldehyde formed initially is further oxidized.
R-CH₂-OH --(Strong Oxidizing Agent)--> R-CHO --(Strong Oxidizing Agent)--> R-COOH(Carboxylic Acid)
- Mild Oxidation (e.g., PCC - Pyridinium Chlorochromate): Forms aldehydes. PCC is selective and stops at the aldehyde stage.
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Secondary Alcohols (R₂CH-OH):
- Oxidation (mild or strong): Forms ketones. Ketones are generally resistant to further oxidation under typical conditions.
R₂CH-OH --(Oxidizing Agent)--> R₂C=O(Ketone)
- Oxidation (mild or strong): Forms ketones. Ketones are generally resistant to further oxidation under typical conditions.
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Tertiary Alcohols (R₃C-OH):
- Tertiary alcohols do not undergo oxidation under normal conditions because they lack a hydrogen atom on the carbon bearing the -OH group. Strong conditions will cause C-C bond cleavage.
Here's a Mermaid diagram to visualize the oxidation pathways:
graph TD
A["Primary Alcohol (RCH2OH)"] -->|Mild Oxidation (e.g., PCC)| B["Aldehyde (RCHO)"]
A -->|Strong Oxidation (e.g., K2Cr2O7)| C["Carboxylic Acid (RCOOH)"]
B -->|Further Strong Oxidation| C
D["Secondary Alcohol (R2CHOH)"] -->|Oxidation| E["Ketone (R2C=O)"]
F["Tertiary Alcohol (R3COH)"] -->|No Oxidation (under normal conditions)| F_No["No Reaction"]
3. Worked Example
Let's consider the reaction of a primary alcohol, ethanol (CH₃CH₂OH), under different conditions.
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Reaction with Sodium Metal:
2CH₃CH₂OH + 2Na → 2CH₃CH₂O⁻Na⁺ + H₂
Ethanol reacts with sodium to produce sodium ethoxide and hydrogen gas. This shows its acidic nature. -
Reaction with HBr:
CH₃CH₂OH + HBr → CH₃CH₂Br + H₂O
Ethanol reacts with hydrobromic acid to form bromoethane (an alkyl halide) and water. This is a nucleophilic substitution. -
Dehydration with concentrated H₂SO₄:
CH₃CH₂OH --(conc. H₂SO₄, 170°C)--> CH₂=CH₂ + H₂O
Ethanol undergoes dehydration at high temperatures in the presence of concentrated sulfuric acid to form ethene (an alkene) and water. -
Oxidation with PCC:
CH₃CH₂OH --(PCC)--> CH₃CHO
Ethanol is oxidized by Pyridinium Chlorochromate (PCC) to ethanal (acetaldehyde), an aldehyde. PCC stops the oxidation at the aldehyde stage. -
Oxidation with K₂Cr₂O₇/H⁺:
CH₃CH₂OH --(K₂Cr₂O₇/H⁺)--> CH₃CHO --(K₂Cr₂O₇/H⁺)--> CH₃COOH
Ethanol is strongly oxidized by acidified potassium dichromate to ethanoic acid (acetic acid), a carboxylic acid.
4. Key Takeaways
- Alcohols can act as weak acids (O-H bond cleavage) or as nucleophiles (C-O bond cleavage after protonation).
- The acidity of alcohols decreases as the number of alkyl groups increases (primary > secondary > tertiary).
- Nucleophilic substitution of alcohols usually requires converting the -OH group into a better leaving group (like -OH₂⁺).
- Dehydration of alcohols to alkenes follows Zaitsev's rule, favoring the most substituted alkene.
- The outcome of alcohol oxidation depends on the type of alcohol and the strength of the oxidizing agent.
- Primary alcohols oxidize to aldehydes (mild) or carboxylic acids (strong).
- Secondary alcohols oxidize to ketones.
- Tertiary alcohols are generally resistant to oxidation.
Common Mistakes to Avoid:
* Assuming all alcohols are strong acids; they are weak acids, weaker than water.
* Forgetting to convert -OH to a good leaving group before nucleophilic substitution.
* Confusing primary alcohol oxidation products: mild conditions yield aldehydes, strong conditions yield carboxylic acids.
* Trying to oxidize tertiary alcohols to aldehydes or ketones under normal conditions.
* Not considering Zaitsev's rule for dehydration products when multiple options exist.
5. Now Try It
You have 1-propanol (CH₃CH₂CH₂OH) and 2-propanol (CH₃CH(OH)CH₃). For each alcohol, describe the major organic product formed when it reacts with:
1. Excess HBr.
2. PCC.
3. Concentrated H₂SO₄ at high temperature.
What success looks like: You should be able to correctly identify the product for each reaction and explain why that product is formed based on the alcohol's structure (primary vs. secondary) and the reaction type.
Frequently asked about Chemical Properties of Alcohols
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