Coordinate Geometry: Distance and Section Formulae
From the Coordinate geometry, Applications of trignometry and circles of 10th cbse curriculum
TL;DR
You'll learn how to find the distance between any two points using their coordinates and how to find the coordinates of a point that divides a line segment. These two powerful formulas, the Distance Formula and the Section Formula, are fundamental tools for solving many geometry problems. They help you analyze geometric shapes and positions numerically.
1. The Mental Model
Imagine you have a map with grid lines (that's your coordinate plane). The Distance Formula helps you measure the direct "as the crow flies" distance between two locations on this map. The Section Formula helps you find a specific point on the road connecting two locations, like a rest stop that's a certain fraction of the way from one to the other.
2. The Core Material
The Distance Formula
The Distance Formula helps you calculate the length of the line segment connecting two points in a coordinate plane. If you have two points, let's say $A(x_1, y_1)$ and $B(x_2, y_2)$, the distance $AB$ is given by:
$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
It's essentially an application of the Pythagorean theorem. You're finding the hypotenuse of a right-angled triangle formed by the points and lines parallel to the axes.
The Section Formula
The Section Formula helps you find the coordinates of a point that divides a line segment in a given ratio. Let's say a point $P(x, y)$ divides the line segment joining $A(x_1, y_1)$ and $B(x_2, y_2)$ internally in the ratio $m_1 : m_2$. Then the coordinates of $P$ are:
$x = \frac{m_1x_2 + m_2x_1}{m_1 + m_2}$
$y = \frac{m_1y_2 + m_2y_1}{m_1 + m_2}$
It's important to remember that $m_1$ is multiplied by the coordinates of the second point ($B$), and $m_2$ by the coordinates of the first point ($A$).
Midpoint Formula (A special case of Section Formula)
When the ratio $m_1 : m_2$ is $1:1$, the point $P$ is the midpoint of the line segment. In this case, the Section Formula simplifies to:
$x = \frac{1x_2 + 1x_1}{1 + 1} = \frac{x_1 + x_2}{2}$
$y = \frac{1y_2 + 1y_1}{1 + 1} = \frac{y_1 + y_2}{2}$
This is known as the Midpoint Formula.
Here's a diagram illustrating the connection:
graph TD
A["Line Segment AB"] --> B{"Needs to be divided?"}
B -- Yes --> C{"In what ratio?"}
B -- No --> D{"Need length of AB?"}
C -- "Ratio m1:m2" --> E["Apply Section Formula"]
C -- "Ratio 1:1 (Midpoint)" --> F["Apply Midpoint Formula"]
D -- Yes --> G["Apply Distance Formula"]
E --> H["Get coordinates of dividing point P"]
F --> I["Get coordinates of midpoint M"]
G --> J["Get length (distance) AB"]
3. Worked Example
Let's find the distance between points $A(2, 3)$ and $B(5, 7)$, and then find the coordinates of the point $P$ that divides $AB$ in the ratio $2:1$.
Part 1: Distance between A and B
Using the Distance Formula:
$A(x_1, y_1) = (2, 3)$
$B(x_2, y_2) = (5, 7)$
$AB = \sqrt{(5 - 2)^2 + (7 - 3)^2}$
$AB = \sqrt{(3)^2 + (4)^2}$
$AB = \sqrt{9 + 16}$
$AB = \sqrt{25}$
$AB = 5$ units
Part 2: Coordinates of P dividing AB in ratio 2:1
Using the Section Formula with $m_1 = 2$ and $m_2 = 1$:
$x_1 = 2, y_1 = 3$
$x_2 = 5, y_2 = 7$
$x = \frac{m_1x_2 + m_2x_1}{m_1 + m_2} = \frac{2(5) + 1(2)}{2 + 1} = \frac{10 + 2}{3} = \frac{12}{3} = 4$
$y = \frac{m_1y_2 + m_2y_1}{m_1 + m_2} = \frac{2(7) + 1(3)}{2 + 1} = \frac{14 + 3}{3} = \frac{17}{3}$
So, the point $P$ that divides $AB$ in the ratio $2:1$ has coordinates $(4, \frac{17}{3})$.
4. Key Takeaways
- The Distance Formula helps you calculate the length of a line segment connecting two points.
- The Section Formula finds the coordinates of a point that divides a line segment in a specific ratio.
- The Midpoint Formula is a special case of the Section Formula where the ratio is 1:1.
- Both formulas are based on the coordinates of the given points and involve basic arithmetic operations.
- Remember to square the differences in coordinates before adding them in the Distance Formula.
- When using the Section Formula, cross-multiply the ratios with the opposite point's coordinates.
Common Mistakes to Avoid:
- Mixing up $x_1, y_1$ with $x_2, y_2$: Always be consistent with which point is $(x_1, y_1)$ and which is $(x_2, y_2)$.
- Incorrectly applying the ratio in Section Formula: Ensure $m_1$ is with $x_2, y_2$ and $m_2$ is with $x_1, y_1$.
- Arithmetic errors: Squaring negative numbers (like $(2-5)^2 = (-3)^2 = 9$) should always result in a positive value.
- Forgetting the square root: In the Distance Formula, the final step is to take the square root.
5. Now Try It
Given points $C(-1, -2)$ and $D(3, 4)$:
1. Calculate the distance between $C$ and $D$.
2. Find the coordinates of the midpoint of $CD$.
3. Find the coordinates of the point $Q$ that divides the line segment $CD$ in the ratio $3:2$.
Success looks like: You'll have three sets of answers – a single number for the distance, a pair of coordinates for the midpoint, and another pair of coordinates for point $Q$. Make sure you write down each step clearly.
Frequently asked about Coordinate Geometry: Distance and Section Formulae
Study this next
Get the full Coordinate geometry, Applications of trignometry and circles of 10th cbse curriculum
Clone the complete plan to your dashboard for unlimited AI-generated notes, practice quizzes, and a personalised revision schedule.
Save this course free