How to handle circle equations on the SAT

SAT Mathematics Equation of a circle

Read centre and radius straight from standard form, convert from expanded form, and avoid the two sign traps the SAT uses.

What the examiner is testing

Whether you can move between the two forms of a circle equation. The SAT rarely asks you to draw one — it asks for the centre, the radius, or the diameter, and hides the answer one algebraic step away.

$$ (x - h)^2 + (y - k)^2 = r^2 $$

Centre \( (h, k) \), radius \( r \). Note that the equation stores \( r^2 \), not \( r \) — the single most common slip on this topic.

Reading it straight off

For \( (x - 3)^2 + (y + 5)^2 = 49 \):

  • \( h = 3 \), because the bracket says \( x - 3 \).
  • \( k = -5 \), because \( y + 5 \) is \( y - (-5) \).
  • \( r = \sqrt{49} = 7 \), not 49.

Centre \( (3, -5) \), radius 7. The signs flip. A bracket reading \( +5 \) means a coordinate of \( -5 \).

Worked example: converting from expanded form

A circle is given by \( x^2 + y^2 - 6x + 4y - 12 = 0 \). Find its centre and radius.

Step 1 — group x terms and y terms, move the constant right.

$$ (x^2 - 6x) + (y^2 + 4y) = 12 $$

Step 2 — complete the square on the x group. Half of \( -6 \) is \( -3 \), and \( (x-3)^2 \) introduces \( +9 \):

$$ x^2 - 6x = (x - 3)^2 - 9 $$

Step 3 — complete the square on the y group. Half of \( 4 \) is \( 2 \), and \( (y+2)^2 \) introduces \( +4 \):

$$ y^2 + 4y = (y + 2)^2 - 4 $$

Step 4 — substitute both back.

$$ (x - 3)^2 - 9 + (y + 2)^2 - 4 = 12 $$

Step 5 — move the constants to the right.

$$ (x - 3)^2 + (y + 2)^2 = 25 $$

Answer: centre \( (3, -2) \), radius \( \sqrt{25} = 5 \). If the question asks for the diameter, it is 10 — read the question twice, because both appear as answer choices.

Check: expand back mentally. \( (x-3)^2 + (y+2)^2 = x^2 - 6x + 9 + y^2 + 4y + 4 \), which equals 25, so \( x^2 + y^2 - 6x + 4y = 12 \). That matches the original.

The three mistakes that lose marks

1. Giving \( r^2 \) as the radius. The right-hand side is the radius squared. An answer of 25 when the radius is 5 is a distractor the SAT deliberately offers.

2. Copying the sign from the bracket. \( (y + 2)^2 \) means \( k = -2 \). Both signs flip, every time.

3. Forgetting to move the introduced constants. Completing the square adds a number you must subtract again. Track them on the left before shifting them right.

30-second recap

Standard form gives centre and radius directly, with the signs reversed and the radius square-rooted. To get there from expanded form: group, complete the square on each variable, move every constant to the right. Then check whether the question wanted radius or diameter.

Common questions

(x - h)^2 + (y - k)^2 = r^2, where (h, k) is the centre and r is the radius. The signs inside the brackets are the opposite of the centre coordinates, which is the trap most questions rely on.

Group the x terms and the y terms, complete the square on each, then move the constants to the right-hand side. The Desmos calculator on the digital SAT can check your answer but not show working.

Substitute it into the left-hand side. Less than r squared is inside, equal is on the circle, greater is outside.

More revision guides

Written by StudyAI to cover a topic students ask about often. It uses its own worked example — no exam board's questions are reproduced here.