Maths — Number Systems and Operations + 5 more topics

$N_{(b)} = \sum_{i=-m}^{n-1} d_i \cdot b^i$

where $d_i$ is the digit at position $i$, and $b$ is the base.

Conversion from Decimal to Binary (Integer Part - Division Method):
To convert $(13)_{10}$:
$13 \div 2 = 6$ remainder $1$ (LSB)
$6 \div 2 = 3$ remainder $0$
$3 \div 2 = 1$ remainder $1$
$1 \div 2 = 0$ remainder $1$ (MSB)
Reading remainders from bottom up: $(1101)_2$.