Electromotive Force and Internal Resistance
TL;DR
Electromotive Force (EMF) is the maximum potential difference a source can provide, even when no current flows. Internal resistance in a power source causes some energy to be lost, reducing the actual voltage available at its terminals. This internal resistance makes the terminal voltage drop as more current is drawn from the source.
1. The Mental Model
Imagine a perfect battery as a pump that always pushes water with the same force (EMF). But inside the battery there's a narrow pipe (internal resistance) that resists the water flow, so less "pressure" (voltage) comes out of the battery when you're using a lot of water.
2. The Core Material
When we talk about a power source like a battery or a generator, we often think of it as having a fixed voltage. However, in reality, every power source has some inherent resistance inside it. This is called internal resistance, and it affects the voltage you actually get out of the source.
Let's break down the key terms:
2.1 Electromotive Force (EMF, $\mathcal{E}$)
EMF is the total energy per unit charge that a power source can provide. Think of it as the "strength" of the source when it's just sitting there, not powering anything. It's the maximum potential difference across its terminals when no current is flowing (i.e., in an open circuit). EMF is measured in Volts (V).
2.2 Internal Resistance (r)
This is the opposition to the flow of charge within the power source itself. No power source is perfectly efficient; some energy is always lost as heat due to this internal resistance when current flows. Internal resistance is measured in Ohms ($\Omega$).
2.3 Terminal Voltage (V)
This is the actual voltage you measure across the terminals of the power source when it's connected to a circuit and providing current. Because of internal resistance, the terminal voltage is always less than the EMF when current is flowing.
Here's the crucial relationship:
Terminal Voltage (V) = EMF ($\mathcal{E}$) - (Current (I) $\times$ Internal Resistance (r))
So, $V = \mathcal{E} - Ir$.
This equation shows that as the current (I) drawn from the source increases, the voltage drop across the internal resistance ($Ir$) increases, and consequently, the terminal voltage (V) decreases. If no current flows ($I=0$), then $V = \mathcal{E}$, meaning the terminal voltage equals the EMF.
You can also think of the total resistance in the circuit as the