Introduction to Le Chatelier's Principle and Concentration Changes

From the Le Chatelier's Principle curriculum · Updated Jun 09, 2026

Introduction to Le Chatelier's Principle and Concentration Changes

TL;DR

Le Chatelier's Principle predicts how chemical equilibria respond to changes in concentration, temperature, or pressure. When you change reactant or product concentrations, the equilibrium shifts to counteract that change. You'll learn to predict and explain these shifts quantitatively.

1. The Mental Model

Chemical equilibria are like a balanced seesaw that automatically adjusts when you add weight to either side. If you increase reactants, the equilibrium shifts right to make more products. If you increase products, it shifts left to make more reactants. That's the whole idea.

2. The Core Material

Understanding Chemical Equilibrium

Before diving into Le Chatelier's Principle, you need to understand what equilibrium means. In a reversible reaction like A + B ⇌ C + D, equilibrium occurs when the forward and reverse reaction rates are equal. The concentrations of all species remain constant, but reactions continue in both directions.

The equilibrium constant K expresses this mathematically:
K = [C][D]/[A][B]

At a given temperature, K is always the same value regardless of starting concentrations. This is crucial for understanding Le Chatelier's Principle.

Le Chatelier's Principle Defined

Henri Le Chatelier stated that when a system at equilibrium experiences a change in concentration, temperature, or pressure, the equilibrium shifts to oppose that change. Think of it as nature's way of maintaining balance.

For concentration changes specifically: if you increase the concentration of any species, the equilibrium shifts away from that species. If you decrease a concentration, the equilibrium shifts toward that species.

How Concentration Changes Work

Let's use the reaction N₂ + 3H₂ ⇌ 2NH₃ as our example. At equilibrium, the reaction quotient Q equals K:
Q = [NH₃]²/[N₂][H₂]³ = K

Now, imagine you suddenly add more N₂. This increases the denominator, making Q < K. The system is no longer at equilibrium. To restore equilibrium (make Q = K again), the reaction must shift right, consuming N₂ and H₂ while producing more NH₃.

Conversely, if you remove some NH₃, you decrease the numerator, again making Q < K. The equilibrium shifts right to produce more NH₃ and restore the K value.

If you add NH₃, you increase the numerator, making Q > K. Now the equilibrium shifts left, converting some NH₃ back to N₂ and H₂ until Q equals K again.

The key insight: the equilibrium always shifts to partially undo whatever change you made. It doesn't completely reverse your change, but it minimizes the effect.

graph LR
    A["Add Reactant"] --> B["Q < K"]
    B --> C["Shift Right"]
    C --> D["More Product Formed"]
    E["Add Product"] --> F["Q > K"]
    F --> G["Shift Left"]
    G --> H["More Reactant Formed"]

3. Worked Example

Let's work through a specific problem. Consider this equilibrium at 500°C:
H₂ + I₂ ⇌ 2HI

Initially, we have:
- [H₂] = 0.20 M
- [I₂] = 0.15 M
- [HI] = 0.60 M
- K = 12.0 at 500°C

Now we suddenly add 0.10 M more H₂, making [H₂] = 0.30 M.

First, let's check if we're still at equilibrium:
Q = [HI]²/[H₂][I₂] = (0.60)²/(0.30)(0.15) = 0.36/0.045 = 8.0

Since Q = 8.0 < K = 12.0, the equilibrium must shift right.

Let's say x moles of H₂ react. Then:
- [H₂] = 0.30 - x
- [I₂] = 0.15 - x
- [HI] = 0.60 + 2x

At the new equilibrium:
12.0 = (0.60 + 2x)²/[(0.30 - x)(0.15 - x)]

Solving this equation (which involves some algebra), we get x ≈ 0.041 M.

Final concentrations:
- [H₂] = 0.259 M
- [I₂] = 0.109 M
- [HI] = 0.682 M

Notice that adding H₂ did increase the final amount of HI produced, but some of the added H₂ remains unreacted. The equilibrium shifted right as predicted, partially consuming the added reactant.

4. Key Takeaways

4.1 Most Important Concepts

  • Le Chatelier's Principle states that equilibria shift to oppose applied changes
  • Adding reactants shifts equilibrium toward products; adding products shifts toward reactants
  • The equilibrium constant K remains unchanged when concentrations change at constant temperature
  • Equilibrium shifts are partial responses—they don't completely undo the applied change
  • The reaction quotient Q compared to K tells you which direction the equilibrium will shift
  • Removing a species has the opposite effect of adding it
  • These principles apply to all reversible chemical reactions at equilibrium

4.2 Common Misconceptions

  • Misconception: Adding a reactant will completely react to form products. Reality: Only a portion reacts; some excess remains.
  • Misconception: The equilibrium constant changes when you change concentrations. Reality: K only changes with temperature.
  • Misconception: Catalysts affect equilibrium position. Reality: Catalysts speed up both forward and reverse reactions equally, reaching equilibrium faster without changing final concentrations.
  • Misconception: Le Chatelier's Principle applies to rate of reaction. Reality: It predicts equilibrium position changes, not how fast changes occur.

4.3 Compare & Contrast

Change Applied Effect on Q vs K Equilibrium Shift Final Result
Add Reactant Q < K Shifts Right More product formed
Add Product Q > K Shifts Left More reactant formed
Remove Reactant Q > K Shifts Left Less product present
Remove Product Q < K Shifts Right Less reactant present

5. Now Try It

Practice with this equilibrium: 2SO₂ + O₂ ⇌ 2SO₃. Start with [SO₂] = 0.50 M, [O₂] = 0.30 M, [SO₃] = 0.40 M, and K = 4.0. Calculate what happens when you add 0.20 M more SO₂. Find the new equilibrium concentrations and verify your answer makes sense with Le Chatelier's Principle.

Success looks like: You correctly identify that Q < K after adding SO₂, predict a rightward shift, set up the ICE table, and solve for new concentrations where more SO₃ is present than initially.


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